Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The equation of the hyperbola whose foci are (6, 5), (–4, 5) and eccentricity 
is
A
= 1
B
= 1
C
= –1
D
None of these
Text Solution
Verified by ExpertsThe correct answer is:
A
Here S 1 ≡ ≡ ( 6, 5); S 2 ≡ ≡ (–4, 5) , e = 5/ 4, so that S 1 S 2 = 10 ⇒ ⇒ 2ae = 10 ⇒ ⇒ a = 4.
And b 2 = a 2 (e 2 – 1) = 16 
= 9.
Centre of the curve is (1, 5) ⇒ ⇒ Equation of required hyperbola is;
.
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